CMAT 2016 - Exam Strategy

Check the best strategy planning by Endeavor Gurus for CMAT exam when there is less than 10 days left to appear for the exam.

XAT 2016 Exam Analysis and Answer Key

XAT once again stood out with its high quality paper. On one hand where it stood firm on the declared test pattern, unlike CAT where there were hidden surprises, on the other hand where it claimed on easy paper…Hmm…that understandably didn’t happen much.

Read More at - http://www.endeavorcareers.com/gurus-speak/772-xat-2016-exam-analysis

XAT 2016 Answer Key - http://www.endeavorcareers.com/gurus-speak/773-xat-2016-answer-key

Best Preparation Strategy - 30 Days to CMAT

The countdown has begun. With just 30 days to go for CMAT  2016, this is probably going to be the most important phase of your CMAT preparations. This is quite a tricky phase, because almost all of you are already done with solving all the modules at least twice and are pretty much confident about your concepts but, still there is a that stupid feeling of unpreparedness or fear of exam that keeps lurking around in some corner of your mind. 

Believe me when I say this, the only way to overcome your fear of exams is to face it as Dale Carnegie aptly said “Do the thing you fear, and continue to do so. This is the quickest and surest way of all victory over fear”.

Read Complete Strategy at - http://www.endeavorcareers.com/gurus-speak/761-30-days-to-cmat-preparation-strategy

Arithmetic & Algebraic Problems - A LEGACY PUZZLE

Question: A man left legacies to his three sons and to a hospital, amounting in all to $1,320.00. If he had left the hospital legacy also to his first son, that son would have received as much as the other two sons together. If he had left it to his second son, he would have received twice as much as the other two sons together. If he had left the hospital legacy to his third son, he would have received then thrice as much as the first son and second son together. Find the amount of each legacy.

Answer: The legacy to the first son was $55.00, to the second son $275.00, to the third son $385.00, and to the hospital $605.00, making $1,320.00 in all.

Arithmetic & Algebraic Problems - THE STAIRCASE RACE

Question: This is a rough sketch of the finish of a race up a staircase in which three men took part. Ackworth, who is leading, went up three steps at a time, as arranged; Barnden, the second man, went four steps at a time, and Croft, who is last, went five at a time. Undoubtedly Ackworth wins. But the point is, how many steps are there in the stairs, counting the top landing as a step?

I have only shown the top of the stairs. There may be scores, or hundreds, of steps below the line. It was not necessary to draw them, as I only wanted to show the finish. But it is possible to tell from the evidence the fewest possible steps in that staircase. Can you do it?

Answer: If the staircase were such that each man would reach the top in a certain number of full leaps, without taking a reduced number at his last leap, the smallest possible number of steps would, of course, be 60 (that is, 3 X 4 X 5). But the sketch showed us that A. taking three steps at a leap, has one odd step at the end; B. taking four at a leap, will have three only at the end and C. taking five at a leap, will have four only at the finish. Therefore, we have to find the smallest number that, when divided by 3, leaves a remainder I, when divided by 4 leaves 3, and when divided by 5 leaves a remainder 4. This number is 19. So there were 19 steps in all, only 4 being left out in the sketch.

Arithmetic & Algebraic Problems - TIMING THE CAR

Question: "I was walking along the road at three and a half miles an hour," said Mr. Pipkins, "when the car dashed past me and only missed me by a few inches." "Do you know at what speed it was going?" asked his friend. "Well, from the moment it passed me to its disappearance round a corner.

I took twenty-seven steps and walking on reached that corner with one hundred and thirty-five steps more." "Then, assuming that you walked, and the car ran, each at a uniform rate, we can easily work out the speed."

Answer: As the man can walk 27 steps while the car goes 162, the car is clearly going six times as fast as the man. The man walks 3 1/2 miles an hour: therefore the car was going at 21 miles an hour.

Arithmetic & Algebraic Problems - HILL CLIMBING

Question: Weary Willie went up a certain hill at the rate of one and a half miles per hour and came down at the rate of four and a half miles per hour, so that it took him just six hours to make the double journey. How far was it to the top of the hill?

Answer: It must have been 6 3/4 miles to the top of the hill. He would go up in 4 1/2 hours and descend in 1 1/2 hours.