10 November 2015

Arithmetic & Algebraic Problems - BOYS AND GIRLS

Question: Nine boys and three girls agreed to share equally their pocket money. Every boy gave an equal sum to every girl, and every girl gave another equal sum to every boy. Every child then possessed exactly the same amount. What was the smallest possible amount that each then possessed?

Answer: Every boy at the start possessed 12¢, and he gave 1¢ to every girl. Every girl held 36¢, of which she gave 3¢ to every boy. Then every child would have 18¢.

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