Question: At what time are the two hands of a clock so situated that, reckoning as minute points past XII, one is exactly the square of the distance of the other?
Answer: The time is 6 3/4 minutes past IX, when the hour hand is 45 9/16 (the square of 6 3/4) minutes past XII. If we allow fractions less than a minute point, there is also the solution, five seconds (one-twelfth of a minute) past XII o'clock.
No comments:
Post a Comment