CAT 2015 - Important Dates And Major Changes In Exam Pattern

Indian Institute of Management, Ahmedabad (IIM-A) announced the details for Common Admission Test (2015) on 26th July 2015.

Important Dates 

• Registration period:  06th August to 20th September 2015.
• Exam Date: 29th November, 2015 (one day), in two slots (Forenoon & Afternoon Sessions).
• Download of Admit Card: 15th October 2015, 1:00 PM to Exam Day
• Results Date: 2nd Week January

Important Features of CAT 2015

•  Exam will be conducted in 136 cities across India, in 650 test sites.
• Duration of the examination has been increased to 180 minutes instead of 170 minutes. 

There will be 3 sections:

1. ‘Quantitative Aptitude (QA) : 34 questions (60 minutes)
2. ‘Data Interpretation & Logical Reasoning (DILR): 32 questions (60 minutes)
3. ‘Verbal and Reading Comprehension (VRC) : 34 questions (60 minutes)

• Some questions may not carry multiple choices and will have to be typed on the screen.             Also, use of basic on-screen calculator for computation will be allowed. 
• One will not be able to shift among sections.
• Format of the examination will be available on the CAT website from 15th October 2015.
• The Normalization process to be implemented shall adjust for location and scale differences of score distributions across different forms. After normalization across different forms the scores shall be further normalized across different sections and the scaled scores obtained by this process shall be converted into percentiles for purposes of short listing.

Eligibility Criteria

• The candidate must hold a Bachelor’s Degree, with at least 50% marks or equivalent CGPA
• For the candidates  appearing in the final year of bachelor’s degree/equivalent qualification      examination and those who have completed degree, the last date of submission for programme certificate is June 30, 2016.
• IIMs may verify eligibility at various stages of the selection process, the details of which are     provided at the website www.iimcat.ac.in

Contact Information

Website: www.iimcat.ac.in
Email ID: cat2015@iimahd.ernet.in
Help Desk Number: 18002660207 (Monday to Saturday 09:00AM to 06:00PM)

Puzzle on Logical Reasoning - Five friends with surname Batliwala, Pocketwala, Talawala, Chunawala and Natakwala have their first name and middle name....

Question:  Five friends with surname Batliwala, Pocketwala, Talawala, Chunawala and Natakwala have their first name and middle name as follow.

Four of them have a first and middle name of Paresh.

Three of them have a first and middle name of Kamlesh.

Two of them have a first and middle name of Naresh.

One of them have a first and middle name of Elesh.

Pocketwala and Talawala, either both are named Kamlesh or neither is named Kamlesh.

Either Batliwala and Pocketwala both are named Naresh or Talawala and Chunawala both are named Naresh.

Chunawala and Natakwala are not both named Paresh.

Who is named Elesh?

Answer:    Pocketwala is named Elesh.

Solution: 

From (1) and (7), it is clear that Batliwala, Pocketwala and Talawala are named Paresh. From (6) and (5), if Pocketwala or Talawala both are named Kamlesh, then either of them will have three names i.e. Paresh, Kamlesh and Naresh. Hence, Pocketwala and Talawala both are not named Kamlesh. It means that Batliwala, Chunawala and Natakwala are named Kamlesh. Now it is clear that Talawala and Chunawala are named Naresh. Also, Pocketwala is named Elesh.

Puzzle on Number System - What is the remainder left after dividing 1! + 2! + 3! + … + 100! By 7?

Question:  What is the remainder left after dividing 1! + 2! + 3! + … + 100! By 7?

Answer:    After Dividing we Get 5 as remainder

Solution: 

7! onward all terms are divisible by 7 as 7 is one of the factor. So there is no remainder left for those terms i.e. remainder left after dividing 7! + 8! + 9! + ... + 100! is 0.

The only part to be consider is

= 1! + 2! + 3! + 4! + 5! + 6!

= 1 + 2 + 6 + 24 + 120 + 720

= 873

The remainder left after dividing 873 by 7 is 5

Hence, the remainder is 5.